f(-3)=-2(-3)^2-5(-3)+4

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Solution for f(-3)=-2(-3)^2-5(-3)+4 equation: 



f(-3)=-2(-3)^2-5(-3)+4

We move all terms to the left:

f(-3)-(-2(-3)^2-5(-3)+4)=0

We add all the numbers together, and all the variables

f(-3)-1=0

We multiply parentheses

-3f-1=0

We move all terms containing f to the left, all other terms to the right

-3f=1

f=1/-3

f=-1/3

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